Cell potential practice problems

Chemistry Unit 9. Try each one, then open the worked solution. The Credit Sprint app generates unlimited new versions with fresh numbers.

Problem 1.

The cathode half-reaction has E° = +0.77 V and the anode half-reaction has E° = -0.94 V (both as reductions). What is E°cell?

Show solution

E°cell = E°cathode − E°anode = 0.77 − (-0.94) = 1.71 V.

Problem 2.

The cathode half-reaction has E° = +0.71 V and the anode half-reaction has E° = -1.96 V (both as reductions). What is E°cell?

Show solution

E°cell = E°cathode − E°anode = 0.71 − (-1.96) = 2.67 V.

Problem 3.

The cathode half-reaction has E° = +0.54 V and the anode half-reaction has E° = -1.44 V (both as reductions). What is E°cell?

Show solution

E°cell = E°cathode − E°anode = 0.54 − (-1.44) = 1.98 V.

Problem 4.

The cathode half-reaction has E° = +0.49 V and the anode half-reaction has E° = -1.18 V (both as reductions). What is E°cell?

Show solution

E°cell = E°cathode − E°anode = 0.49 − (-1.18) = 1.67 V.

Problem 5.

The cathode half-reaction has E° = +1.44 V and the anode half-reaction has E° = -1.25 V (both as reductions). What is E°cell?

Show solution

E°cell = E°cathode − E°anode = 1.44 − (-1.25) = 2.69 V.

Problem 6.

The cathode half-reaction has E° = +1.39 V and the anode half-reaction has E° = -0.67 V (both as reductions). What is E°cell?

Show solution

E°cell = E°cathode − E°anode = 1.39 − (-0.67) = 2.06 V.