Dilution practice problems

Chemistry Unit 4. Try each one, then open the worked solution. The Credit Sprint app generates unlimited new versions with fresh numbers.

Problem 1.

What volume (mL) of 2 M stock solution is needed to prepare 250 mL of 1 M solution?

Show solution

V₁ = M₂V₂ ÷ M₁ = (1)(250) ÷ 2 = 125 mL.

Problem 2.

What volume (mL) of 12 M stock solution is needed to prepare 500 mL of 0.5 M solution?

Show solution

V₁ = M₂V₂ ÷ M₁ = (0.5)(500) ÷ 12 = 20.8 mL.

Problem 3.

What volume (mL) of 3 M stock solution is needed to prepare 500 mL of 0.5 M solution?

Show solution

V₁ = M₂V₂ ÷ M₁ = (0.5)(500) ÷ 3 = 83.3 mL.

Problem 4.

What volume (mL) of 6 M stock solution is needed to prepare 100 mL of 0.1 M solution?

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V₁ = M₂V₂ ÷ M₁ = (0.1)(100) ÷ 6 = 1.67 mL.

Problem 5.

What volume (mL) of 12 M stock solution is needed to prepare 250 mL of 1 M solution?

Show solution

V₁ = M₂V₂ ÷ M₁ = (1)(250) ÷ 12 = 20.8 mL.

Problem 6.

What volume (mL) of 3 M stock solution is needed to prepare 250 mL of 0.25 M solution?

Show solution

V₁ = M₂V₂ ÷ M₁ = (0.25)(250) ÷ 3 = 20.8 mL.