Ideal gas law practice problems

Chemistry Unit 3. Try each one, then open the worked solution. The Credit Sprint app generates unlimited new versions with fresh numbers.

Problem 1.

What volume (L) is occupied by 2 mol of an ideal gas at 273 K and 0.5 atm? (R = 0.08206 L·atm/mol·K)

Show solution

V = nRT/P = (2)(0.08206)(273) ÷ 0.5 = 89.6 L.

Problem 2.

What volume (L) is occupied by 2 mol of an ideal gas at 273 K and 2 atm? (R = 0.08206 L·atm/mol·K)

Show solution

V = nRT/P = (2)(0.08206)(273) ÷ 2 = 22.4 L.

Problem 3.

What volume (L) is occupied by 0.25 mol of an ideal gas at 273 K and 1 atm? (R = 0.08206 L·atm/mol·K)

Show solution

V = nRT/P = (0.25)(0.08206)(273) ÷ 1 = 5.6 L.

Problem 4.

What volume (L) is occupied by 2 mol of an ideal gas at 400 K and 1.5 atm? (R = 0.08206 L·atm/mol·K)

Show solution

V = nRT/P = (2)(0.08206)(400) ÷ 1.5 = 43.8 L.

Problem 5.

What volume (L) is occupied by 2 mol of an ideal gas at 350 K and 2 atm? (R = 0.08206 L·atm/mol·K)

Show solution

V = nRT/P = (2)(0.08206)(350) ÷ 2 = 28.7 L.

Problem 6.

What volume (L) is occupied by 0.5 mol of an ideal gas at 400 K and 0.5 atm? (R = 0.08206 L·atm/mol·K)

Show solution

V = nRT/P = (0.5)(0.08206)(400) ÷ 0.5 = 32.8 L.