Credit Sprint / Practice problems / Logistic population growth
Logistic population growth practice problems
Biology Unit 8. Try each one, then open the worked solution. The Credit Sprint app generates unlimited new versions with fresh numbers.
A population has r = 1, N = 250 and carrying capacity K = 1000. Use dN/dt = rN(K − N)/K. What is dN/dt?
Show solution
1 × 250 × (1000 − 250) ÷ 1000 = 187.5 per unit time.
A population has r = 1, N = 250 and carrying capacity K = 1000. Use dN/dt = rN(K − N)/K. What is dN/dt?
Show solution
1 × 250 × (1000 − 250) ÷ 1000 = 187.5 per unit time.
A population has r = 0.4, N = 900 and carrying capacity K = 1000. Use dN/dt = rN(K − N)/K. What is dN/dt?
Show solution
0.4 × 900 × (1000 − 900) ÷ 1000 = 36 per unit time.
A population has r = 0.2, N = 1500 and carrying capacity K = 2000. Use dN/dt = rN(K − N)/K. What is dN/dt?
Show solution
0.2 × 1500 × (2000 − 1500) ÷ 2000 = 75 per unit time.
A population has r = 0.5, N = 1800 and carrying capacity K = 2000. Use dN/dt = rN(K − N)/K. What is dN/dt?
Show solution
0.5 × 1800 × (2000 − 1800) ÷ 2000 = 90 per unit time.
A population has r = 1, N = 1500 and carrying capacity K = 2000. Use dN/dt = rN(K − N)/K. What is dN/dt?
Show solution
1 × 1500 × (2000 − 1500) ÷ 2000 = 375 per unit time.